||
wyz=[1 2 3 4 6 3 7 9 0 2 4 7 1 8 4 5 11 23 89 33 54 61 3 5]
a=sort(wyz) %将wyz排序给a
size(find(a<5)) %给出wyz中小于5的项的个数
size(find(a>5 & a<10)) %给出wyz中大于5小于10的项的个数
.......
wyz1==[2 3 4 6 3 7 9 0 2 4 7 1 8 4 5 11 23 89 33 54 61 3 5 5]
b=wyz-wyz1 %wyz的隔项差
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